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Zaret
a fost răspuns

Efectuatii: (2V7 + 1) la puterea 2
(3-V7) la doua
(3V2+2V5) la puterea 2

Răspuns :

(2√7+1)^2=
=(2√7)^2+2×2√7×1+1^2=
=28+4√7+1=29+4√7

(3-√7)^2=
=3^2-2×3×√7+(√7)^2=
=9-6√7+7=16-6√7

(3√2+2√5)^2=
=(3√2)^2+2×3√2×2√5+(2√5)^2=
=18+12√10+20=38+12√10

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