Răspuns :
Aplicam teorema sinusului
[tex] \frac{a}{sinA}= \frac{b}{sinB}= \frac{c}{sinC} =2R \\ din \\ \frac{a}{sinA} =2R \\ \frac{10}{sin30}=2R \\ 20=2R \\ R=10 [/tex]
[tex] \frac{a}{sinA}= \frac{b}{sinB}= \frac{c}{sinC} =2R \\ din \\ \frac{a}{sinA} =2R \\ \frac{10}{sin30}=2R \\ 20=2R \\ R=10 [/tex]