a)Fie a nr. initial de bilete
1)a-1/3a=b
2)b-2/5b-10=c
3)c-1/10c=99
3) rezulta ca 10/10c-1/10c=99;9/10c=99;c=110
2) rezulta ca 5/5b-2/5b-10=110;3/5b=120;b=200
1) rezulta ca 3/3a-1/3a=200;2/3a=200;a=300
99+110+200+300=709 bilete in total.
b)in a treia zi s-au vandut 110 bilete;110x3.5=385 euro
