[tex](x+ \sqrt3)^2-10=x^2-(\sqrt3 +2)^2 \\ \\ x^2+2\cdot x\cdot \sqrt3 +3 -10 = x^2 - (3+2\cdot \sqrt3 \cdot 2+4) \\ \\ x^2-x^2+2\sqrt3x-7 = -(7+4\sqrt3) \\ \\ 2\sqrt3x-7 = -7-4\sqrt3 \\ \\ 2\sqrt3x=7-7-4\sqrt3 \\ \\ 2\sqrt3x=-4\sqrt3 \\ \\ x = \dfrac{-4\sqrt3}{2\sqrt3} \\ \\ x = -2[/tex]
