In tr.MON
NO=9u;
MO=12u;
m(Din toate rezulta conform T.P. ca
MN^2=MO^2+NO^2=12^2+9^2=
3^2(4^2+3^2)=3^2×5^2=15^2;
MN=¬/(15^2)=15(u);
NP=NO+OP=9u+16u=25u;
In tr. MOP;
MO=12u;
PO=16u;
m(Din toate 4=>conform T.P. ca MP^2=MO^2+PO^2;
MP^2=12^2+16^2=4^2(3^2+4^2)=
=4^2·5^2=20^2=>MP=¬/(20^2)=20(u);
In tr. MNP;
MN^2+MP^2=15^2+20^2=
5^2(3^2+4^2)=5^2·5^2=(25u)^2;
NP^2=(25u)^2;
Din cele 2 => conform R.T.P. ca tr.MNP este dreptunghic
