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Anuska23
a fost răspuns

Calculeaza: (3 la puterea 202 • 3 la puterea a 3-a + 3 la puterea 303 : 3 la puterea 98 + 9 la puterea 100 • 3 la puterea a 5-a) : 3 la puterea 205 - 1 la puterea 2013

Răspuns :

Alexandravert
(3^202*3^3+3^303:3^98+9^100*3^5):3^205-1^2013=
=[3^205+3^205+(3^2)^100*3^5]:3^205-1=
=(2*3^205+3^200*3^5):3^205-1=
=(2*3^205+3^205):3^205-1=
=(3*3^205)/3^205-1=
=3-1=
=2

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