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Calculati: 2^30 : 2^25 + 2^4^0 - 2^1 x[128 : 2^5 +2^3 :(2 x 2^4 - 24^1)] Va rog mult!!!! (V intors inseama la putere)

Răspuns :

Renatemambouko
2^30 : 2^25 + 2^4^0 - 2^1 x[128 : 2^5 +2^3 :(2 x 2^4 - 24^1)]=
=2^5 + 2^1 - 2^1 x[2^7 : 2^5 +2^3 :(2^5 - 2^3×3)]=
=2^5 + 2^1 - 2^1 x[2^2 +2^3 :2^3(2^2 - 3)]=
=2^5 + 2^1 - 2^1 x[2^2 +2^3 :2^3(4 - 3)]=
=2^5 + 2^1 - 2^1 x[2^2 +2^3 :2^3]=
=2^5 + 2^1 - 2^1 x(2^2 +1)=
=2^5 + 2^1 - 2^1 x 5=
=2^5 + 2^1(1 - 5)=
=2^5 + 2^1(-4)=
=2^5 - 2^1×2^2=
=2^5 - 2^3=
=2^3(2^2 - 1)=
=2^3×3=
=8×3=24

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