Răspuns :
Fie x lungimea drumului, atunci:
In prima zi x/2 metri
In a doua zi x/3+20 metri
In a 3 zi 680metrii sau x-x/2-x/3-20
x-x/2-x/3-20=680
x-x/2-x/3=700
6x-3x-2x=4200
x=4200
Drumul are 4200metri sau 4,2km
In prima zi 4200/2=2100m
In a doua 4200/3+20=1420m
In a treia zi 680m
In prima zi x/2 metri
In a doua zi x/3+20 metri
In a 3 zi 680metrii sau x-x/2-x/3-20
x-x/2-x/3-20=680
x-x/2-x/3=700
6x-3x-2x=4200
x=4200
Drumul are 4200metri sau 4,2km
In prima zi 4200/2=2100m
In a doua 4200/3+20=1420m
In a treia zi 680m
x-distanta
I zi: x/2
II zi:1/3*x/2+20=x/6+20
III zi:680
x/2+x/6+20+860=x
aducem la acelasi numitor si il eliminam...
3x+x+4200=6x
4200=2x
x=2100 m
I zi: x/2
II zi:1/3*x/2+20=x/6+20
III zi:680
x/2+x/6+20+860=x
aducem la acelasi numitor si il eliminam...
3x+x+4200=6x
4200=2x
x=2100 m