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Hriscastefanutove4ba
a fost răspuns

calculati: a=(-1)^3x(-2)+(-1)^n+2x3-(-1)^2n+3x(-4), n e N

Răspuns :

Renatemambouko
a=(-1)³x(-2)+(-1)ⁿ+2x3-(-1)²ⁿ+3x(-4)=
n par
=(-1)x(-2)+1+6-1-12=
=2+6-12=-4
n impar
=(-1)x(-2)-1+6-1-12=
=2-1+6-1-12=
=-6

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