asa cum l=ai scis, conform ordinii operatiilor,
2x-7/1000-2/1005=2x-1000/7-1005/2
7/1000+2/1005=1000/7+1005/2
7/1000+2/1005<1/10+1/500=0,102
1000/7+1005/2<100+500=600
deci egalitatea este FALSA
x∈∅
dac insa ai
(X-14)/2000+(x-4)/2010=(x-2000)/14+(x-2010)/4
atunci, trecand numerele in stanga si x-ii in dreapta
2000/14+2010/4-14/2000-4/2010= x(1/14+1/4+1/2000+1/2010)
1000/7+1005/2-7/1000-2/1005=x(1/14+1/4+1/2000+1/2010)
x=(1000/7+1005/2-7/1000-2/1005): (1/14+1/4+1/2000+1/2010)
sa il calculeze cine doreste!
