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Rebecarebeca12345
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Determinati numerele x,y,z stiind ca x+y+z=27 ,x/3=y/4 si y/6=z/3.

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Răspuns :

x+y+z=27
x/3=y/4→ x=3y/4
y/6=z/3 →z=3y/6=y/2

3y/4+y+y/2=27 |·4
3y+4y+2y=108
9y=108
y=108:9=12

x=3y/4=3·12/4=3·3=9
z=y/2=12/2=6

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