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Biancaandreeaf
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Afla a din egaliatea 75:[(a×3+72:8)×9-19×6]+27×8=217.
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Răspuns :

Rebecarebeca12345
75 : [(a×3+72:8)×9-19×6]+27×8=217
75 : [(3a+9) x 9 -114]+216=217
75:(27a+81-114) =217-216
75 : (27a+81-114) =1
27a +81-114 =75
27a+81=75+114
27a+81=189
27a=189-81
27a=108
a=108:27
a=4
75:[(a×3+72:8)×9-19×6]+27×8=217
75:[(a×3+9)×9-114]+216=217
75:[(a×3+9)×9-114]=217-216=1
(a×3+9)×9-114=75×1=75
(a×3+9)×9=114+75=189
a×3+9=189:9=21
a×3=21-9=12
a=12:3
a=4