Răspuns :
ax²+bx+c=x²-2x+1-(x²-4x+4)
=x²-2x+1-x²+4x-4
=2x-3
=>a=0, b=2 si c=-3
=>a+b+c=2-3
=(-1)
=x²-2x+1-x²+4x-4
=2x-3
=>a=0, b=2 si c=-3
=>a+b+c=2-3
=(-1)
(x-1)^2-(x-2)^2=(x-1+x-2)(x-1-x+2)=2x-3
ax^2+bx+c=2x-3 ⇒a=0,b=2,c=-3
a+b+c=2-3=-1
ax^2+bx+c=2x-3 ⇒a=0,b=2,c=-3
a+b+c=2-3=-1