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a fost răspuns

Efectuați a.(3^2-2^3):(6^2-7×5)=
b.(4^3-23^0):3^2+2^2×8=
c.(2^2-3)^100+5:[3^2-4×(3^1-3^0)]×1^2013=
d.21^2-2×{11^2+21:(2-1)+2×[1+2^3×(1+2)+2^4-2^1]}

CA ROG REPEDE!!

Răspuns :

Slavitescudora
a) (9-8):(36-35)=1:1=1

b) (64-1):9+4×8=63:9+32=7+32=39

c) (4-3)^100+5:[9-4×(3-1)]×1=1+5:[9-4×2]×1=1+5:[9-8]×1=1+5:1×1=1+5×1=1+5=6

d) 441-2×{121+21:1+2×[1+8×3+16-2]}
441-2×{121+21+2×[1+24+14]}
441-2×{142+2×39}
441-2×{142+78}=441-2×220=441-440=1
SaReMaRe
Pai:a.(9-8):(36-35)=
1:1=1

b.(64-1):9+4×8=
63:9+32=
7+32=39

c. (4-3)^100+5:[9-4×(3-1)]×1
=1+5:[9-4×2]×1
=1+5:[9-8]×1
=1+5:1×1
=1+5×1
=1+5
=6

Si ultimul:d. 441-2×{121+21:1+2×[1+8×3+16-2]}
441-2×{121+21+2×[1+24+14]}
441-2×{142+2×39}
441-2×{142+78}
=441-2×220
=441-440
=1

Pa si succes!!!!!!

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