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Rezolvati ecuatiile: 
a) (2x²-5x-12)(x²-2)=0
b) (3x²+2x-5)(4x²-5x+1)=0
c) [tex] \frac{ x^{2} +5}{ x^{2} +x+ 1} [/tex] - 2=0
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Răspuns :

Atillasmell123
a)(2x²-5x-12)(x²-2)=0
2x²-5x-12=0
∆=121
x1=4
x2=-3/2

x²-2=0
(x-√2)(x+√2)=0
x3=√2
x4=-√2

b)(3x²+2x-5)(4x²-5x+1)=0
3x²+2x-5=0
∆=4+60=64
x1=-2+8/6=1
x2=-10/6=-5/3

4x²-5x+1=0
∆=25-16=9
x3=5+3/8=1
x4=5-3/8=-1/4

c il ai in poza
Vezi imaginea Atillasmell123

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