👤
a fost răspuns

Sa se imparta numarul 1200 in parti invers proportionale cu : 5/4; 5/3; 5/12; 5/6

Răspuns :

Renatemambouko
5a/4=k    a=4k/5
5b/3=k    b=3k/5
5c/12=k  c=12k/5
5c/6=k    d=6k/5
a+b+c+d=1200
4k/5+3k/5+12k/5+6k/5=1200
25k/5=1200
5k=1200
k=1200/5=240
a=4k/5=4×240/5=192
b=3k/5=3×240/5=144
c=12k/5=12×240/5=576
d=6k/5=6×240/5=288

Alte intrebari