CxH2xO + CyH2yO ⇒ C(x+y)H(2x+2y-2)O + H2O
X Y Z
Z + 2[Ag(NH3)2]OH ⇒ acid + 2Ag↓ + 4NH3 + H2O
nAg = 2n Z = 2,7/108 = 0,025 moli n Z. = 0,0125 moli
M Z= 1,05/0,0125 = 84 g/mol
12(x+y) +2x + 2y - 2 + 16 = 84 14x + 14y = 70 x +y = 5
X = CH3-CH=O Y = CH3-CH2-CH=O