Răspuns :
2017·(1-1/2)(1-1/3)...(1-1/2017)=
=2017((2-1)/2)·((3-1)/3)·....((2017-1)2017)
=2017(1/2)(2/3)·....(2016/2017), simplificam
=1
=2017((2-1)/2)·((3-1)/3)·....((2017-1)2017)
=2017(1/2)(2/3)·....(2016/2017), simplificam
=1