Răspuns :
impartim prima relatie cu b²
atiunci 4(a/b)²+9=12(a/b)
nOtam a/b=x
ecuatia devine
4x²-12x+9=0
(2x-3)²=0
solutie unica x=3/2
a/b=3/2
in raportul cerut impatim si numaratorul si numitorul cu b
raportul devine
(4(a/b)+3)/(2*(a/b)+6)=
(4*3/2 +3)/(2*3/2+6)=
(6+3)/(3+6)=
=9/9=1
AS DIFFICULT AS THAT!!
atiunci 4(a/b)²+9=12(a/b)
nOtam a/b=x
ecuatia devine
4x²-12x+9=0
(2x-3)²=0
solutie unica x=3/2
a/b=3/2
in raportul cerut impatim si numaratorul si numitorul cu b
raportul devine
(4(a/b)+3)/(2*(a/b)+6)=
(4*3/2 +3)/(2*3/2+6)=
(6+3)/(3+6)=
=9/9=1
AS DIFFICULT AS THAT!!