y²=7-4√3=4-4√3+3=4-2*2*√3+(√3)²=(2-√3)²
atunci
y1,2=+-√(2-√3)²= +-|2-√3|= +-(2-√3)
y1=2-√3∈R
y2=-2+√3 ∈R
cum y1,2 ∈R\Q⇒in Q, S=∅
traducere din "limba matematica " in "limba romana"
ecuatia are 2 solutii reale, irationale
deci in R are 2 solutii, iar in Q nu are solutie
