[tex]|-6x+5|\ \textgreater \ 1\leftrightarrow -6x+5\ \textless \ -1 \ sau \ -6x+5\ \textgreater \ 1\\
6x\ \textgreater \- 6,x\ \textgreater \ 1 \rightarrow x\in(1+\infty)
sau\ -6x\ \textgreater \ -4; x\ \textless \ \frac{2}{3}, \ x\in(-\infty, \frac{2}{3})\\
x\in (-\infty,\frac{2}{3})\cup (1,+\infty)[/tex]
