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(√2-√3)²-(√3-2)(√3+2)+2√6

Răspuns :

SignOfTheTimes
Salut,

(√2-√3)²-(√3-2)(√3+2)+2√6 =
(√2)²-2•√2•√3+(√3)²-[(√3)²-2²]+2√6 =
2-2√6+3-(3-4)+2√6 =
5+1 = 6.

Succes! :3
[tex]( \sqrt{2} - \sqrt{3} )^2-( \sqrt{3} -2)( \sqrt{3} +2)+2 \sqrt{6} =\\\\ \sqrt{2} ^2-2 \sqrt{2} \sqrt{3} + \sqrt{3} ^2- \sqrt{3} ^2-2^2+2 \sqrt{6} =\\\\ 2 -2 \sqrt{6} +3-3+4+2 \sqrt{6} =\\\\ 2+4=6[/tex]

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