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a fost răspuns

n = 4^{0} + 4^{1} + 4^{2} + ... + 4^{117}
n = ?

"^" inseamna "la puterea"

Răspuns :

AcelOm
[tex]n=1+4+4^2+...+4^{117}[/tex]
[tex]=\frac{4^{118}-1}{3}[/tex]
[tex]\frac{4^{118}-1}{3}:10[/tex]
[tex]=\frac{4^{118}-1}{3}\cdot\frac{1}{10}[/tex]
[tex]=\frac{4^{118}-1}{30}[/tex]