Răspuns :
axb=9/5
c=20/27
ax(bxc)=axbxc=9/5x20/27=4/3
se foloseste proprietaea imultirii asociativitatea ax(bxc)=(axb)xc
c=20/27
ax(bxc)=axbxc=9/5x20/27=4/3
se foloseste proprietaea imultirii asociativitatea ax(bxc)=(axb)xc
de la ordinea operatiilor stim ca ax(bxc)=axbxc=(axb)xc
9/5x20/27=4/3
9/5x20/27=4/3