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Suricata1
a fost răspuns

se stie ca a/8=b/9=c/10 so a+b+c=54,calculation a, b, c

Răspuns :

Lita1
54/8+9+10=54/27=2
a=8×2=16
b=9×2=18
c=10×2=20
Mihaelap
a/8 = b/9 = c/10 = k
a = 8k
b = 9k
c = 10k
8k + 9k + 10k = 54
27k = 54
k = 54 : 27
k = 2
a = 8 * 2 = 16
b = 9 * 2 = 18
c = 10 * 2 = 20
a + b + c = 54
16 + 18 + 20 = 54
54 = 54