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Biancamoldovan
a fost răspuns

cum calculez 1+2+2^2+2^3+...+2^9

Răspuns :

[tex]s=1+2+2^2+...+2^9\\ s=1+1+2+2^2+...+2^9-1=2+2+2^2+...+2^9-1=\\ 2^2+2^2+...+2^9-1=\\ 2^3+2^3+...+2^9-1=\\ ...\\ s=2^9+2^9-1\\ s=2^{10}-1 [/tex]
SignOfTheTimes
Salut,

o să o iau băbește :)

2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
2^6 = 64
2^7 = 128
2^8 = 256
2^9 = 512

1+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9 =
1+2+4+8+16+32+64+128+256+512 =
3+12+48+192+768 =
15+240+768 =
255+768 = 1023.



Succes! :3

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