Răspuns :
aplicand formula distantei si tinand ciont ca 2-(-2)=4 si ca(-1-2)=-3, rezulta imediat
√(4²+(-3)²)=√(16+9)=√25=5
√(4²+(-3)²)=√(16+9)=√25=5
distanta dintre 2 puncte
[tex] \sqrt{(x2-x1)^{2} +(y2-y1)^{2}}= \sqrt{(-2-2)^{2}+[2-(-1)]^{2}}= \sqrt{(-4)^{2} + 3^{2}} = \sqrt{16+9}=5 [/tex]
[tex] \sqrt{(x2-x1)^{2} +(y2-y1)^{2}}= \sqrt{(-2-2)^{2}+[2-(-1)]^{2}}= \sqrt{(-4)^{2} + 3^{2}} = \sqrt{16+9}=5 [/tex]