Răspuns :
Conform definitiilor:
Ade 3 luate cate 2= 3!/1!=6
Cde 3 luate cate 2=3!/(2!)*(1!)=6/2=3
si impartirea este 6/3=2
Ade 3 luate cate 2= 3!/1!=6
Cde 3 luate cate 2=3!/(2!)*(1!)=6/2=3
si impartirea este 6/3=2
[tex]\it A_3^2:C_3^2 = A_3^2:\dfrac{A_3^2}{P_2}= A_3^2\cdot\dfrac{P_2}{A_3^2} =P_2 = 1\cdot2 = 2[/tex]