Răspuns :
Salut ,
(–1)ⁿ + (–1)ⁿ⁺¹ + (–1)ⁿ⁺² + (–1)ⁿ⁺³ = (–1)ⁿ [1 + (—1)¹ + (–1)² + (–1)³] = (–1)ⁿ · (1 – 1 + 1 – 1) = (–1)ⁿ · 0 = 0 si (–1)ⁿ · (–1)ⁿ⁺¹ · (–1)ⁿ⁺² · (–1)ⁿ⁺³ · 0 = 0 => afirmatia este adevarata.
(–1)ⁿ + (–1)ⁿ⁺¹ + (–1)ⁿ⁺² + (–1)ⁿ⁺³ = (–1)ⁿ [1 + (—1)¹ + (–1)² + (–1)³] = (–1)ⁿ · (1 – 1 + 1 – 1) = (–1)ⁿ · 0 = 0 si (–1)ⁿ · (–1)ⁿ⁺¹ · (–1)ⁿ⁺² · (–1)ⁿ⁺³ · 0 = 0 => afirmatia este adevarata.