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(35+x)•10-25=325
(35+x)•10=350
35+x=35
x=35-35
x=0
______________________
(30•10)-(4•a+50•2)=100
300-(4a+100)=100
4a+100=200
4a=100
a=25
(35+x)•10=350
35+x=35
x=35-35
x=0
______________________
(30•10)-(4•a+50•2)=100
300-(4a+100)=100
4a+100=200
4a=100
a=25
(35+x)*10-25=325
(35+x)*10 = 325+25 / = 350
35+x = 350:10 / = 35
x = 35 - 35
x = 0
(30*10)-(4*a+50*2)=100
300 -4a -100 = 100
200 - 4a=100
4a=200-100 /=100
a=100:4
a=25
(35+x)*10 = 325+25 / = 350
35+x = 350:10 / = 35
x = 35 - 35
x = 0
(30*10)-(4*a+50*2)=100
300 -4a -100 = 100
200 - 4a=100
4a=200-100 /=100
a=100:4
a=25