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Aflați numărul X din egalitatea 5•53-{4•[5+(x-2)•7]:3}•6=1

Răspuns :

Primăvară2017
5•53-{4•[5+(x-2)•7]:3}•6=1

265-{4•[5+(x-2)•7]:3}•6=1

{4•[5+(x-2)•7]:3}•6=265-1

{4•[5+(x-2)•7]:3}•6=264

4•[5+(x-2)•7]:3=264:6

4•[5+(x-2)•7]:3= 44

4•[5+(x-2)•7]=44×3

4•[5+(x-2)•7]=132

5+(x-2)•7=132:4

5+(x-2)•7=33

(x-2)•7=33-5

(x-2)•7=28

x-2=28:7

x-2=4

x=4+2

x=6
5•53-{4•[5+(x-2)•7]:3}•6=1
5•53-[4•(5+7x-14):3]•6=1
5•53-[(4•(7x-9):3]•6=1
265-[(28x-36):3]•6=3
3•265-(28x+36)•6=3
795-168x+216=3
1008=168x
x=1008:168
x=6

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