Răspuns :
Notam cu a,b,c cele trei numere naturale consecutive.
|---| un segment
a |---|
b |---| +1
c |---| +2
b=a+1
c=b+1=a+1+1=a+2
a+b+c=243
=>a+a+1+a+2=243
3a+2=243
3a=243-3=240
a=240:3
a=80
b=a+1=80+1=81
c=a+2=80+2=82
|---| un segment
a |---|
b |---| +1
c |---| +2
b=a+1
c=b+1=a+1+1=a+2
a+b+c=243
=>a+a+1+a+2=243
3a+2=243
3a=243-3=240
a=240:3
a=80
b=a+1=80+1=81
c=a+2=80+2=82
a+a+1+a+2=243<=>3a+3=243<=>3a=240<=>a=240:3<=>a=80=>
=>a+1=81 ; a+2=82
=>a+1=81 ; a+2=82