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Dianasabina2
a fost răspuns

daca a+b=4 si c=5 calculeaza [4a+c+4b)*(3c-(2a+2b)]

Răspuns :

Renatemambouko
a+b=4 si c=5

 [4a+c+4b)×(3c-(2a+2b)]= [4(a+b)+c)*(3c-2(a+b)]= (4×4+5)×(3×5-2×4)=
=(16+5)×(15-8)=21×7=147
HawkEyed
[(4a+c+4b) x (3c-(2a+2b)] = 
[( 4(a+b) + c)  x ( 3c - 2(a+b)] =
[( 4 x 4 + 5 ) x ( 3 x 5 - 2 x 4)]=
[ ( 16 + 5) x ( 15 - 8 )]=
21 x 7 = 147 

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