[tex]1)\frac{a+b+c}{3}=19[/tex]
a+b+c=57
a=b+5
c=b-2
b+5+b+b-2=57
3b+3=57
3b=54
b=18
a=23; c=16
2) In A apar 2, 3, 5, 6, 7, iar in B apar 3, 5, 7
Sa vedem daca in A pot aparea si 1 si 4
Daca apar doar in A, atunci A\B={1, 2, 4, 6}, gresit
Daca apar in ambele multimi, atunci [tex]A\cap B=\{1, 3, 4, 5, 7\}[/tex], gresit
Daca apar doar in B, se respecta conditiile
A={2, 3, 5, 6, 7}; B={1, 3, 4, 5, 7}