Răspuns :
Alcoolii secundari se oxideaza energic la cetone, dar se rupe catena si se continua oxidarea resturilor pana la acizi carboxilici.
Deci din 3 hexanol rezulta acid propanoic
Deci din 3 hexanol rezulta acid propanoic
CH3-CH2-CH(OH)-CH2-CH2-CH3+[O]⇒CH3-CH2-COOH+CH3CH2-COOH
CH3-CH2-CH(OH)-(CH2)2-CH3 + [O] ⇒ CH3COOH + CH3(CH2)2-COOH
CH3-CH2-CH(OH)-(CH2)2-CH3 + [O] ⇒ CH3COOH + CH3(CH2)2-COOH