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ajutati-ma va rog !Dau 50 de puncte!repede!
De la 29 la 39!
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Ajutatima Va Rog Dau 50 De PuncterepedeDe La 29 La 39Va Rog Din Suflet class=

Răspuns :

Rodi11
29)
(2-1/2)^2:(3/2)^2=
=(2/1 -1/2)^2:(3/2)^2=
=(2×2-1 tot ăsta supra/2)^2:(3/2)^2=
=(4-1totul supra/2)^2 :(3/2)^2=
=(3/2)^2:(3/2)^2=
=(3/2)^2-2=
=(3/2)^1=
=3/2

30)
(1+ 1/11 × 1 intreg2/9)^2=
=(1/1+ 1/11 × 1×9+2tot ăsta supra/9)^2=
=(1/1 + 1/11 ×11/9)^2=
=(1/1 + 1×1 totul supra/1×9)^2=
=(1/1 + 1/9)^2=
=(9×1+1 tot asta supra/9)^2=
=(10/9)^2

31)
(3-1/3)^2 × (9/8)^2=
=(3/1 -1/3)^2 × (9/8)^2=
=(3×3-1tot ăsta supra/3)^2 × (9/8)^2=
=(8/3)^2 ×(9/8)^2 se simplifica 8 cu 8 dau ambele 1 si 9 cu 3 la noua ramane 3 si la 3 ramane 1
=((8/3)^2) ×((9/8)^2)=
=(1×3 totul supra/1×1)^2=
=(3/1)^2=
=3^2=
=9
(poate nu ati invatat modul acesta încă sa te uiti in caietul tău la lecții )

32)
2/5:(1/2 -1/3)^2 - 14 intregi2/5=
=2/5: (3×1-2×1 tot asta supra/6)^2 - 14×5+2tot ăsta supra/5=
=2/5 : (1/6)^2 - 72/5=
=2/5 ×(6/1)^2 -72/5=
=2/5× 6^2 - 72/5=
=2/5 × 36/1 -72/5=
=2×36totul supra/5×1 -72/5=
=72/5 -72/5=
=0

33)
3/4:(2/3-1/2)^2- 10 întregi 2/7=
=3/4 :( 2×2-3×1tot ăsta supra/6)^2 - 10×7+2tot ăsta supra/7=
=3/4:(4-3totul supra/6)^2 - 77+2totsupra/7=
=3/4 :(1/6)^2- 79/7=
=3/4 ×6^2 -79/7 =
=3/4 ×36/1 -79/7=
=3×36totul /4×1 -79/7=
=108/4 -79/7=
=7×108-4×79 tot ăsta supra/28=
=756-316totul supra/28=
=440/28 simplificat cu 4=
=110/7

34 )

[(1intreg1/2-3/4)^2-(3/4-1/2)^2]:(1 -5/6)^2=
=[(1×2+1tot asta supra/2 -3/4)^2]:(1/1-5/6)^2=
=[(3/2 -3/4)^2]:(6×1-5tot ăsta supra /6)^2=
=(2×3-3tot ăsta supra/4)^2 :(1/6)^2=
=(3/4)^2 ×6^2=
=(3/4)^2 ×36=
=3^2/4^2 ×36=
=9/16 ×36/1=
=9×9tot supra/4×1=
=81/4

35)
2intregi1/3+[(3/2+:4/9× 2intregi1/4):1/9+11/4]:1/4=
=2×3+1tot ăsta supra/3+[(3/2:4/9× 2×4+1tot asta supra/4):1/9+11/4]:1/4=
=7/3+[(3/2 :4/9×9/4):1/9+11/4]:1/4=
=7/3+[(3/2×9/4×9/4):1/9+11/4]:1/4=
=7/3+[( 3×9tot ăstasupra /2×4 ×9/4):1/9+11/4]:1/4=
=7/3+[(27/8 ×9/4)× 9/1 +11/4]:1/4=
=7/3+[(27×9tot supra/8×4)×9/1 +11/4]:1/4=
=7/3+(243/32 ×9/1 +11/4):1/4=
=7/3+(243×9tot asta/32×1 +11/4):1/4=
=7/3+(2187/32 +11/4):1/4=
=7/3+( 2187+8×11 tot acesta supra/32):1/4=
=7/3+(2187+88totul supra/32):1/4=
=7/3+ 2275/32 ×4/1= => (deci aici urma :1/4 dar am inversat cu ×4/1)
=7/3+ 2275×1totul /8×1 =
=7/3 + 2275/8=
=8×7+3×2275tot acesta/24=
=56+6825totul supra /24=
=6881/24

36)
1/2:(1-1/2):[1/5+4×(1/3+1/3:2)]+1/11=
=1/2:(1/1-1/2):[1/5+4/1 ×(1/3+1/3 ×1/2)]+1/11=
=1/2: 2×1-1totăsta /2 : [1/5+4/1 ×(1/3+1/6)]+1/11=
=1/2 : 1/2 :(1/5+4/1× 2×1+1tot asta supra/6)+1/11=
= 1 : (1/5+4/1 × 3/6)+1/11=
=1 : ( 1/5 + 2×3totul supra/1×3)+1/11=
=1 : (1/5+ 6/3)+1/11=
=1 : 3×1+5×6tot acesta supra/15 +1/11=
=1 : 3+30totul supra/15 +1 /11 =
=1: 33/15 +1/11=
=1/1 ×15/33 +1/11=
=1×15totul /1×33 +1/11=
=15/33 +1/11 =
=15+3×1 tot acesta supra/33=
=18/33

37)
36: 4intregi4/5+(5intregi1/2×8întregi 1/11-1intreg1/8×18intregi2/9):5/2=
=36: 4×5+4tot asta supra/5 + (5×2+1tot asta supra/2 × 8×11+1tot asta supra/11 - 1×8+1tot asta supra/8 × 18×9+2tot asta supra/9) :5/2=
=36 : 24/5 +(11/2 ×89/11 - 9/8 × 164/9):5/2=
=36/1 × 5/24+(1×89tot supra/2×1 -9/8 ×164/9):5/2=
=6×5totul supra/1×4 +(89/2 - 1×41totul /2×1):5/2=
=30/4+ (88/2 - 41/2):5/2=
=30/4+ 47/2 :5/2=
=30/4 +47/2 ×2/5=
=30/4 + 47×1 totul supra/1×5=
=30/4 + 47/5=
=5×30+4×47tot ăsta supra/20=
=150+188totul supra/20=
=338/20 simplificat cu2=
=169/10

38)
4/19×{1/2+11/15:[1/60+162 ×(1/270+1/405+1/360)]}=
=4/19×{1/2+11/15:[1/60 +162/1×(36×1+24×1+27×1toate acestea supra/ 9720)]}=
=4/19 ×[1/2+11/15:(1/60 +162/1 × 87/9720)]=
=4/19× [1/2+11/15:(1/60+ 1×87totul supra/1×60)]=
=4/19×[1/2+11/15:(1/60+87/60)]=
=4/19×(1/2+11/15:87/60)=
=4/19× (1/2+11/15 ×60/87)=
=4/19×(1/2+ 11×4totul /1×87)=
=4/19×(1/2+ 44/87)=
=4/19× 87×1+44totul /174=
=4/19× 131/174=
=2×131totul /19×87=
=262/1653