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Bucatareasasef
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6+2×[(3×52-22×18÷32+3×11)÷22]=
Va rog dau coroana

Răspuns :

Stoicadenny
6+2×[(3×52-22×18÷32+3×11)÷22]=
=6+2×[(156-396÷32+33)÷33]=
=6+2×[(156-12,37+33)÷33]=
=6+2×[(143,63+33)÷33]=
=6+2×(176,63÷33)=
=6+2×5,35=
=6+10,7=
=16,7

Sper ca e corect. Succes! ^-^
Diana29diu
6+2×[(3×52-22×18÷32+3×11)÷22]=6+2×[(156-396÷32+33)÷22]=
6+2× [(156-12.375+33)÷22]=
6+2×[176.625÷22]=
6+2×8.0284=
6+16.0568=
22.0568

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