Răspuns :
[tex]\it \dfrac{x}{y} =\dfrac{1}{2} \Rightarrow \dfrac{x}{1} =\dfrac{y}{2} =\dfrac{x+y}{1+2} = \dfrac{90^o}{3} =30^o \\\;\\ \\\;\\ \dfrac{x}{1} = 30^o \Rightarrow x = 30^o \\\;\\ \\\;\\ \dfrac{y}{2} =30^o \Rightarrow y = 2\cdot30^o =60^o[/tex]