Răspuns :
x+y=15
3x+3y=3(x+y)=3×15=45
xy+xz=10
x(y+z)=xy+xz=10
xy+xz=-12
y+z=-3
xy+xz=x(y+z)
x•(-3)=-12
x=4
.
3x+3y=3(x+y)=3×15=45
xy+xz=10
x(y+z)=xy+xz=10
xy+xz=-12
y+z=-3
xy+xz=x(y+z)
x•(-3)=-12
x=4
.
Dai factor comun pe 3:
a) 3•(x+y)=3•15=45
b) Inmulteste fiecare termen cu x
x•y+x•z=10
c) Iara factor comun x•(y+z)=-12
x•-3=-12
x= 4
a) 3•(x+y)=3•15=45
b) Inmulteste fiecare termen cu x
x•y+x•z=10
c) Iara factor comun x•(y+z)=-12
x•-3=-12
x= 4