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Deussz
a fost răspuns

se considera functia f(x)=2x³ - 9x²+12x+1
aratati ca f'(x)=6(x-1)(x-2)

Răspuns :

Danutpop
f'(x)= (2x³ - 9x²+12x+1)'
      =6x²+18x+12
      =6(x²+3x+2)
x²+3x+2=0
delta=1 si x1=1;x2=2
formula:ax²+bx+c=a(x-x1)(x-x2)
1(x-1)(x-2)=0
f'(x)=6(x-1)(x-2)
Lucsembourg23
Te gandesti la derivata functiei. 

f'(x)=(2x³ - 9x²+12x+1)'=2·3·x²-9·2·x+12+0=6x²-18x+12=6(x²-3x+2)=6(x²-2x-x+2)=6(x(x-2)-(x-2)=6(x-1)(x-2)

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