Răspuns :
[tex]ab+2ac-ad=ab+ac+ac-ad=a(b+c+c-d)=\\
=\frac{5}{6}(\frac{7}{20}+\frac{1}{24})=\frac{5}{6}(\frac{42}{120}+\frac{5}{120})=\\
=\frac{5}{6}\cdot\frac{47}{120}=\frac{47}{144}[/tex]
a =5/6
b+c = 7/20
c-d =1/24
a*b+2*a*c-a*d=a(b+c+c-d)=5/6 ×(7/20+1/24)=5/6 ×(42+5)/120=(100+47)/120=147/120
b+c = 7/20
c-d =1/24
a*b+2*a*c-a*d=a(b+c+c-d)=5/6 ×(7/20+1/24)=5/6 ×(42+5)/120=(100+47)/120=147/120