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STRATHROWAN
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√(din toata expresia)2+√3 /√(din tot)2-√3 - √(din tot)2-√3 /√(din tot)2+√3 =...va rog explicit

Răspuns :

GreenEyes71
[tex]\dfrac{2+\sqrt3}{2-\sqrt3}+\dfrac{2-\sqrt3}{2+\sqrt3}=\dfrac{(2+\sqrt3)(2+\sqrt3)+(2-\sqrt3)(2-\sqrt3)}{(2-\sqrt3)(2+\sqrt3)}=\\\\=\dfrac{(2+\sqrt3)^2+(2-\sqrt3)^2}{2^2-(\sqrt3)^2}=\dfrac{2^2+2\cdot 2\cdot\sqrt3+(\sqrt3)^2+2^2-2\cdot 2\cdot\sqrt3+(\sqrt3)^2}{4-3}=\\\\=4+4\sqrt3+3+4-4\sqrt3+3=14.[/tex]

Simplu, nu ?

Green eyes.

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