Răspuns :
a) n={1,2}
b)1/n(n-3)€ N => n(n-3)=Divizor de-al lui 1 => n(n-3)={1}
n(n-3)=1 => n x n - 3n=1
=> n x n=1+3n (FALS) -> n=par=>par=impar (F)
n=impar=>impar=par(F) => n=multime vida
b)1/n(n-3)€ N => n(n-3)=Divizor de-al lui 1 => n(n-3)={1}
n(n-3)=1 => n x n - 3n=1
=> n x n=1+3n (FALS) -> n=par=>par=impar (F)
n=impar=>impar=par(F) => n=multime vida