Răspuns :
3 moli KI ---->3moli K+ + 3 moli I-
1 mol orice substanta=6,023*10^23 particule
Nr I- =6,023*10^23*3=1,8069*10^24
1 mol orice substanta=6,023*10^23 particule
Nr I- =6,023*10^23*3=1,8069*10^24
nI⁻ = nKI = 3 moli
nr. ioni = nₓN av. = 3ₓ6,022ₓ10²³= 1,8066ₓ10ₓ²⁴
nr. ioni = nₓN av. = 3ₓ6,022ₓ10²³= 1,8066ₓ10ₓ²⁴