f : R –> R , f( x ) = ( a - 1 )•x+ b+ 2
A ( 1 , -1 ) € Gf <—> f (1) = (-1)
B ( -2 , -7 ) € Gf <—> f ( -2) = -7
( a -1) • 1 + b + 2 = -1
( a -1) • (-2) + b + 2 = -7
a - 1 + b + 2 = -1
- 2a + 2 + b + 2 = -7
2a - 2 + 2b + 4 = -2
-2a + 2 + b + 2 = -7
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\ 3b + 6 = -9
3b = - 15
b = -5
a - 1 -5 + 2= -1
a - 6 + 2 = -1
a - 4 = -1
a = -1 + 4
a = 3
f(x) = 2x - 3