Răspuns :
|2³^22-3²^22|-|9^20-9^22|+|2³^22-2^64|-9^20+2^4^16=
cum 3²>2³, atunci
3^44-2^66-(9^22-9^20)+2^66-2^64-9^20+2^64
cum 9=3², atunci
3^44-2^66-3^44+9^20+2^66-9^20=0+0+0=0
cum 3²>2³, atunci
3^44-2^66-(9^22-9^20)+2^66-2^64-9^20+2^64
cum 9=3², atunci
3^44-2^66-3^44+9^20+2^66-9^20=0+0+0=0
[tex]2^{66}=(2^3)^{22}=8^{22}\\
3^{44}=(3^2)^{22}=9^{22}\\8^{22}\ \textless \ 9^{22}\\
|2^{66}-3^{22}|=3^{44}-2^{66}\\
81^{10}=(3^{4})^{10}=3^{40}\\
9^{22}=(3^2)^{22}=3^{44}\\
3^{40}\ \textless \ 3^{44}\\
|81^{10}-9^{22}|=9^{22}-81^{10}\\
8^{22}=(2^3)^{22}=2^{66}\\
2^{64}\ \textless \ 2^{66}\\
|8^{22}-2^{64}|=2^{66}-2^{64}\\
16^{16}=(2^4)^{16}=2^{64}\\
a=3^{44}-2^{66}-(9^{22}-81^{10})+2^{66}-2^{64}-9^{20}+2^{64}=\\
3^{44}-2^{66}-3^{44}+3^{40}+2^{66}-2^{64}-3^{40}+2^{64}=0
[/tex]