Răspuns :
CH3-CH2-CH2-CH3 -> CH3-CH-CH3
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CH3
M (butan)=M (izobutan)= 4×12+10=48+10=58 g/mol
n=m/M
m=24×58=1392 g izobutan
De pe rectie => ca x=1392 g butan transformat
1740-1392= 348 g butan netransformat
1740 g total butan..........1392g butan transformat
100%........................z%
z=( 100×1392)÷1740=80% butan transformat in izobutan
|
CH3
M (butan)=M (izobutan)= 4×12+10=48+10=58 g/mol
n=m/M
m=24×58=1392 g izobutan
De pe rectie => ca x=1392 g butan transformat
1740-1392= 348 g butan netransformat
1740 g total butan..........1392g butan transformat
100%........................z%
z=( 100×1392)÷1740=80% butan transformat in izobutan