R-NH2 + Cl-CH2-C6H5 = RNH-CH2-C6H5 = C9H13N
⇒ R = CH3-CH2-
produs de reactie = C6H5-CH2-NH-CH2-CH3 M = 135g/mol
n = 270/135 = 2 moli (practic) n teoretic = 2·100/92 = 50/23 moli = =nC6H5-CH2Cl
mC6H5-CH2-Cl pur = 50/23 x 126,5 = 275g
m cu imp. = 275x100/90 = 305,55g
izomeri : CH3-C6H4-NH-C2H5 (O : M: P)
CH3-CH2 - C6H4-NH-CH3 (O : M: P)
(CH3)2C6H3-NH-CH3 O;M : P ; O'; M' ; P')
