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Determinati inaltimea unui paralelipiped dreptunghic care are L=50dm; l=0;02 ;V=60m cubi

Răspuns :

Albatran
L=50dm=5m
l=0,02hm=2m
Volum=Aria bazei *inaltimea ( ORICE baza, ORICE inaltime corespunzatoare ei)
atunci
inaltimea =Volum/aria bazei=60m³/(5m*2m)=60m³/10m²=6m
as simple as that!
Icecon2005
volum paralelipiped dreptunghic = L × l × h = 50 × 0,02 × h = 60 dm³

50 × 0,02 × h = 60 dm³⇒  h = 60:( 50 × 0,02) = 60:1

h  = 60 dm

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