Răspuns :
K2O
Masa moleculara:
M K2O=2*39+16=78+16=94
Raportul de masa:
m K: m O=2*39:16=78:16=39:8
Compozitia procentuala:
78 g K......16 g O......94 g K2O
x...............y............100 g K2O
[tex]x= \frac{7800}{94}=82,98 [/tex]
[tex]y= \frac{1600}{94}=17,02 [/tex]
Deci in K2O exista 82,98% K si 17,02% O.
Masa moleculara:
M K2O=2*39+16=78+16=94
Raportul de masa:
m K: m O=2*39:16=78:16=39:8
Compozitia procentuala:
78 g K......16 g O......94 g K2O
x...............y............100 g K2O
[tex]x= \frac{7800}{94}=82,98 [/tex]
[tex]y= \frac{1600}{94}=17,02 [/tex]
Deci in K2O exista 82,98% K si 17,02% O.
K2O
M = 94g/mol
mK : mO = 78 : 16 = 39 : 8
%K = 78·100/94 = 82,978% %O = 1600/94 = 17,021%
M = 94g/mol
mK : mO = 78 : 16 = 39 : 8
%K = 78·100/94 = 82,978% %O = 1600/94 = 17,021%